Nathan Bahn
Beers Law Study Lab
Introduction:
In this lab, we utilize a spectrometer to observe the transmittance of light at a certain wave length. We experimented to see if the breakwaterarity of a firmness of purpose changes the transmittance of light and the absorbance of that light by the solution. By observing the percent transmittance and the amount of light absorbed, we fag calculate the amount of color absorbing components in the solution. by this process is how we are able to discover the amount of atomic number 29 in the solution.
Experimental Procedure:
250 mL of the copper solution was made by creating 100 mL of the solution, reacting CuO with HNO3, and then diluting to the determine of 250 mL. Using this stock solution, different concentrations were made and placed in the sprectrometer for observation. The absorbances and transmittances were recorded for use when identifying the amount of the color-absorbing copper ions later. A graph was plotted of Absorbance v. molar(a) Concentration easily see the results of the experiment.
Pre-Lab Questions:
1. Absorbance = - Log10T = 2-Log10 (%T)
a) 2 Log (89.95) = .0460f) 2 Log (28.18) = .5501
b) 2 Log (80.91) = .0920g) 2 Log (20.51) = .6880
c) 2 Log (59.02) = .2290h) 2 Log (17.38) = .7600
d) 2 Log (47.75) = .3210i) 2 Log (14.45) = .8401
e) 2 Log (34.83) = .
4580
2. Molar Concentration
1.213 g Cu (1 mol Cu/ 63.546 g Cu) (1 mol [Cu (H2O6)2+]/ 1 mol Cu) (1/ .100 L) = .191 M [Cu (H2O6)2+]
a) M2 = (M1V1)/V2M2 = (.191 M [Cu (H2O6)2+])( 1.0 mL)/ (50.0 mL) = .0038 M
b) (.191 M [Cu (H2O6)2+]) (2.0 mL)/ (50.0 mL) = .0076 M
c) (.191 M [Cu (H2O6)2+]) (5.0 mL)/ (50.0 mL) = .0191 M
d) (.191 M [Cu (H2O6)2+]) (7.0 mL)/ (50.0 mL) = .0267 M
e) (.191 M [Cu (H2O6)2+]) (10.0 mL)/ (50.0 mL) = .0382 M
f) (.191 M [Cu (H2O6)2+]) (12.0 mL)/ (50.0 mL) = .0458 M
g) (.191 M [Cu (H2O6)2+]) (15.0 mL)/ (50.0 mL) = .0573 M
h) (.191 M [Cu (H2O6)2+]) (17.0 mL)/ (50.0 mL) = .0649 M
i) (.191 M [Cu...If you want to get a full essay, order it on our website: Orderessay
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